The Eagles’ star running back has basically been unstoppable.
Saquon Barkley is NFC Offensive Player of the Week for Week 9 of the 2024 NFL season, according to an official league announcement.
Honestly, he deserved this just for the play where he broke two tackles and then jumped over a Jacksonville Jaguars defender BACKWARDS alone. All told, he had 27 carries for 159 yards (5.9 average) and one rushing touchdown … plus three catches for 40 yards and one receiving touchdown in the Eagles’ most recent win.
This marks the third time Barkley is taking home the NFC POTW award this season. He was previously honored in Week 1 and Week 7.
Barkley has now won NFC POTW six times in his career. So, that means he had three in six seasons with the New York Giants … before having three in just eight games with the Philadelphia Eagles. Pretty wild just how good he’s been!
Barkley is logging 5.9 yards per carry (previous career high: 5.0 in 2018) and 6.1 yards per touch (previous career high: 5.8 in 2018) so far. He’s currently on pace for 2,276 yards from scrimmage, which would be the 13th-most ever in a single season.
Honestly, Barkley deserves MVP consideration. He won’t win that since it’s a quarterback award. And he might not win Offensive Player of the Year, either, with Derrick Henry also having an amazing season. But it’s not off the table.
And regardless of individual success, Barkley figures to keep powering the Eagles to team success if he’s able to keep this pace up.
